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IIT JEE Maths Practice Paper – 20- PYQs- Matrices and Determinants

IIT JEE Maths Practice Paper 20 – Matrices and Determinants – PYQs series

Matrices and Determinants are essential topics in JEE Mathematics that test conceptual understanding and application in solving systems of equations, transformations, and inverse operations. This practice set is designed to reinforce these foundational concepts. Topic: Matrices and Determinants 1. If A = [[2, 3], [4, 5]], then |A| is: a) 2 b) -2 c) -1 d) 10 2. If A is a 2×2 matrix such that A² = I, then A is: a) Invertible b) Non-invertible c) Null matrix d) Diagonal 3. For a 3×3 matrix A, the value of |kA| is: a) k³|A| b) k²|A| c) k|A| d) |A| 4. If A is a singular matrix, then |A| is: a) 1 b) -1 c) 0 d) Infinite 5. If A and B are square matrices of the same order and AB = BA, then: a) A and B are equal b) A is symmetric c) A and B commute d) B is a zero matrix 6. If A is an orthogonal matrix, then A⁻¹ is: a) A b) Aᵀ c) -A d) None of these 7. The adjoint of a diagonal matrix is: a) Same diagonal matrix b) Zero matrix c) Inverse matrix d) Transpose 8. The determinant of a skew-symmetric matrix of odd order is: a) 0 b) 1 c) -1 d) Not defined 9. Which matrix has no inverse? a) Identity matrix b) Orthogonal matrix c) Singular matrix d) Diagonal matrix 10. Which of the following is true for all invertible matrices A and B? a) (AB)⁻¹ = A⁻¹B⁻¹ b) (AB)⁻¹ = B⁻¹A⁻¹ c) (A + B)⁻¹ = A⁻¹ + B⁻¹ d) A⁻¹ + B⁻¹ = (AB)⁻¹ Submit Answers

IIT JEE Maths Practice Paper – 19 - PYQs- focused on Probability

IIT JEE Maths Practice Paper – 19 – PYQs- focused on Probability

Part 19 – ProbabilityThis section contains 10 multiple-choice questions from previous IIT JEE exams focused on Probability. These questions are designed to test your understanding of fundamental probability concepts including independent and dependent events, Bayes’ theorem, and conditional probability. Part 19 – IIT JEE Maths Practice Paper: Probability Instructions: Each correct answer gives 4 marks. No negative marking. Choose the best answer for each question and click “Submit” to view your score and explanations. Two dice are thrown simultaneously. What is the probability that the sum is divisible by 4? a) 1/4 b) 1/3 c) 5/18 d) 1/2 A card is drawn from a well-shuffled deck of 52 cards. What is the probability that it is either a red card or a king? a) 7/13 b) 4/13 c) 15/26 d) 8/13 An unbiased coin is tossed 5 times. What is the probability of getting at least 3 heads? a) 1/2 b) 26/32 c) 5/16 d) 11/32 A bag contains 3 red and 5 black balls. Two balls are drawn without replacement. What is the probability both are black? a) 5/14 b) 5/7 c) 5/8 d) 10/21 If A and B are two independent events such that P(A) = 1/3 and P(B) = 1/4, then P(A ∪ B) is: a) 1/2 b) 7/12 c) 1/3 d) 3/4 What is the probability of getting a sum of 7 or 11 when two dice are rolled? a) 2/9 b) 1/6 c) 1/4 d) 5/36 A and B throw a die alternatively. The one who gets a 6 first wins. If A starts, then what is the probability that A wins? a) 5/11 b) 6/11 c) 1/2 d) 7/13 If P(E) = 0.3 and P(F) = 0.4 and E and F are mutually exclusive, find P(E ∪ F). a) 0.12 b) 0.7 c) 1 d) 0.1 If two events A and B are such that P(A) = 0.6, P(B) = 0.5 and P(A ∩ B) = 0.3, then P(A|B) is: a) 0.3 b) 0.6 c) 0.9 d) 0.5 In how many ways can 3 boys and 2 girls be selected from 5 boys and 4 girls? a) 40 b) 60 c) 100 d) 10 Submit

IIT JEE Maths Practice Paper – 18 - PYQs - Binomial Theorem

IIT JEE Maths Practice Paper – 18 – PYQs – Binomial Theorem

Boost your IIT JEE preparation with Part 18 of our Maths Practice Paper series. This set includes carefully selected Binomial Theorem questions based on previous years’ IIT JEE papers. Practice and test your understanding with instant evaluation — answers, score, and explanations included. IIT JEE Maths Practice Paper – Part 18: Binomial Theorem 1. The middle term in the expansion of (1 + x)18 is: 9th term 10th term 8th term 11th term 2. The coefficient of x3 in the expansion of (2 + x)5 is: 40 80 20 60 3. In the expansion of (1 – 3x)4, the term independent of x is: 81 -81 1 -1 4. The general term in the expansion of (a + b)n is: nCr an-r br nCr ar bn-r nCr an br None of the above 5. In the expansion of (1 + x)10, the sum of coefficients is: 10 0 1024 512 Submit

IIT JEE Maths Practice Paper – Part 17 Permutations and Combinations

IIT JEE Maths Practice Paper – Part 17: Permutations and Combinations

Boost your problem-solving skills in Permutations and Combinations with 10 carefully selected multiple-choice questions from previous IIT JEE exams. This set helps you master arrangements, selections, and advanced counting principles essential for scoring well in combinatorics. IIT JEE Maths Practice Paper – Part 17: Permutations and Combinations In how many ways can the letters of the word “APPLE” be arranged? a) 120 b) 60 c) 240 d) 100 How many 4-digit numbers can be formed using digits 1, 2, 3, 4, 5 without repetition? a) 120 b) 625 c) 360 d) 256 Number of ways to choose 3 balls from 5 red and 4 green balls: a) 56 b) 84 c) 126 d) 36 How many ways can 3 boys and 2 girls be seated in a row such that the girls do not sit together? a) 72 b) 36 c) 144 d) 60 Number of circular permutations of 6 distinct objects: a) 720 b) 120 c) 60 d) 5040 A committee of 3 is to be formed from 4 men and 3 women. Number of ways it can be done: a) 35 b) 20 c) 30 d) 25 From the word “BANANA”, how many unique permutations can be formed? a) 60 b) 120 c) 360 d) 720 The number of permutations of 5 different books taken 3 at a time: a) 10 b) 60 c) 20 d) 15 If 5 people sit around a round table, how many seating arrangements are possible? a) 120 b) 24 c) 60 d) 30 The number of ways to divide 10 students into 2 groups of 5 each: a) 126 b) 252 c) 462 d) 180 Submit

IIT JEE Maths Practice Paper – PYQs SET 16 - Complex Numbers

IIT JEE Maths Practice Paper 16 – Complex Numbers – PYQs

Strengthen your understanding of complex numbers with this set of 10 previous years’ MCQs from the IIT JEE exam. This practice set tests your grasp on concepts like modulus, argument, conjugates, equations, and geometric representation. Ideal for quick revision and self-evaluation. IIT JEE Maths Practice Paper – Part 16: Complex Numbers 1. If \( z = 1 + i \), then \( |z|^2 \) equals: a) 1 b) 2 c) √2 d) 0 2. The principal argument of \( -1 – i \) is: a) π/2 b) -π/4 c) -3π/4 d) 3π/4 3. The complex number whose modulus is 1 and argument is π/3 is: a) cos(π/3) + i sin(π/3) b) cos(π/3) – i sin(π/3) c) -cos(π/3) + i sin(π/3) d) -cos(π/3) – i sin(π/3) 4. If \( z = x + iy \) and \( |z| = 5 \), which of the following is true? a) x² – y² = 25 b) x² + y² = 25 c) x + y = 25 d) x – y = 25 5. The value of \( i^{2023} \) is: a) 1 b) -1 c) i d) -i Submit

IIT JEE Maths Practice Paper – Previous Years’ Questions SET 15 - Integration

IIT JEE Maths Practice Paper – 15 – Integration – PYQs

Practice Paper Part 15 – Integration (IIT JEE Maths – Previous Years’ Questions) Sharpen your problem-solving skills with this set of handpicked IIT JEE previous years’ questions from the Integration chapter. These questions are designed to strengthen your conceptual understanding and boost your exam confidence. Each question has detailed explanations to help you learn from mistakes and revise key concepts effectively. IIT JEE Maths Practice Paper – Part 15: Integration 1. ∫ x·ex dx equals: a) x·ex b) ex + C c) (x − 1)·ex + C d) (x + 1)·ex + C 2. ∫ dx / (1 + x2) equals: a) ln|1 + x2| + C b) tan−1(x) + C c) sec−1(x) + C d) x / (1 + x2) + C 3. ∫ sin2(x) dx is: a) x − sin(x)cos(x) + C b) (x/2) − (sin(2x)/4) + C c) −cos2(x) + C d) tan(x) + C 4. ∫ x / √(1 − x2) dx equals: a) −√(1 − x2) + C b) √(1 − x2) + C c) −x√(1 − x2) + C d) −(1 − x2)3/2/3 + C 5. ∫ ex(1 + x) dx equals: a) ex(x − 1) + C b) x·ex + C c) (x + 1)ex + C d) xex − ex + C Submit

Arithmetic Aptitude Time and Distance Practice Questions with Solution - SET 1

Arithmetic Aptitude: Time and Distance Practice Questions with Solution – SET 1

Here are practice questions for Arithmetic Aptitude: Time and Distance Problems asked in Competitive Exams. These questions can be studies for practice of Time and Distance related Arithmetic Aptitude question 🚶‍♂️ Time and Distance – General Question 1 Question: A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour? 3.6 7.2 8.4 10 Show Solution 📘 Step-by-Step Solution: 🧠 Use the basic formula: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] Given distance = 600 meters Time = 5 minutes = \[ 5 \times 60 = 300 \, \text{seconds} \] Speed in m/s: \[ = \frac{600}{300} = 2 \, \text{m/s} \] Convert to km/hr: \[ 2 \times \frac{18}{5} = 7.2 \, \text{km/hr} \] ✅ Final Answer: \(\boxed{7.2 \, \text{km/hr}}\) 🚶 Speed Comparison – Time & Distance Question: If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is: 50 km 56 km 70 km 80 km Show Solution 📘 Step-by-Step Solution: Let the actual distance be \( x \) km. Time taken at 10 km/hr = \[ \frac{x}{10} \] Time taken at 14 km/hr = \[ \frac{x + 20}{14} \] Given: time is same in both cases. So, \[ \frac{x}{10} = \frac{x + 20}{14} \] Cross-multiply: \[ 14x = 10(x + 20) \] \[ 14x = 10x + 200 \] \[ 4x = 200 \Rightarrow x = 50 \] ✅ Final Answer: \(\boxed{50 \, \text{km}}\) 🚌 Speed with and without Stoppages Question: Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? 9 10 12 20 Show Solution 📘 Step-by-Step Solution: Let the total time be 60 minutes (1 hour). Speed without stoppages = 54 km/h ⇒ Bus would cover: \[ \frac{54}{60} = 0.9 \, \text{km per minute} \] Speed with stoppages = 45 km/h ⇒ Bus actually covers: \[ \frac{45}{60} = 0.75 \, \text{km per minute} \] Let the stoppage time be \( x \) minutes. Then, running time = \( 60 – x \) Distance actually covered in \( 60 – x \) minutes at 0.9 km/min: \[ 0.9 \times (60 – x) = 45 \] Simplify: \[ 54 – 0.9x = 45 \] \[ 0.9x = 9 \Rightarrow x = 10 \] ✅ Final Answer: \(\boxed{10 \, \text{minutes}}\) 🚗 Actual Speed Calculation Question: A car travelling with \(\frac{7}{8}\) of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car. \(\frac{17}{6}\) km/hr 25 km/hr 30 km/hr 35 km/hr Show Solution 📘 Step-by-Step Solution: Given time = 1 hr 40 min 48 sec Convert to hours: \[ 1 + \frac{40}{60} + \frac{48}{3600} = 1 + \frac{2}{3} + \frac{2}{150} = \frac{300 + 200 + 4}{180} = \frac{504}{180} = 2.8 \, \text{hrs} \] Speed = Distance / Time = \( \frac{42}{2.8} = 15 \, \text{km/hr} \) This is \(\frac{7}{8}\) of actual speed ⇒ Let actual speed be \( x \) \[ \frac{7}{8}x = 15 \Rightarrow x = \frac{15 \times 8}{7} = \frac{120}{7} = 17.14 \, \text{km/hr} \] ✅ Answer: \(\boxed{\frac{120}{7} = \frac{17}{6}}\) km/hr

IIT JEE Maths Practice Paper – Previous Years’ Questions SET 14

IIT JEE Maths Practice Paper 14 – Vectors PYQs

IIT JEE Maths Practice Paper – Part 14: Vectors Practice 10 multiple-choice questions from past JEE papers based on the topic of Vectors. Click submit to view your result, score, and explanations. If vector a = 2i + 3j and vector b = i − j, then a · b is: 1 -1 3 5 If vectors a and b are such that |a| = 3, |b| = 4 and a · b = 6, then the angle between them is: 30° 45° 60° 90° Two vectors are perpendicular if: Their magnitudes are equal Their dot product is zero Their cross product is zero They have opposite directions The magnitude of the cross product of vectors a and b is equal to: ab cos θ ab ab sin θ a + b The vector i + j is rotated 90° counterclockwise in the plane. Its new direction is: -j + i -i – j -i + j -j – i If a vector has magnitude 5 and makes an angle of 60° with the x-axis, then its x-component is: 5 5√3 5 cos 60° 5 sin 60° If a · b = 0 and a × b ≠ 0, then: Vectors are parallel Vectors are equal Vectors are perpendicular Vectors are same direction Unit vector along vector 3i + 4j is: 3i + 4j (3/5)i + (4/5)j (4/5)i + (3/5)j (5/3)i + (5/4)j The projection of vector a on b is given by: |a||b| sin θ a · b / |b| a × b ab cos θ If a = i + j and b = i − j, then a × b is: 2k -2k 0 i + k Submit

Arithmetic Aptitude Problems on Trains - 5 Solved Questions SET 1

Arithmetic Aptitude : Problems on Trains – 5 Solved Questions – SET 1

Math Test This should show a math equation: \( a^2 + b^2 = c^2 \) 🚆 Train & Platform Problem Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform? 120 m 240 m 300 m None of these Solution 📘 Step-by-Step Solution: Speed of train = \[ 54 \, \text{km/hr} = 54 \times \frac{1000}{3600} = 15 \, \text{m/s} \] Time taken to pass man = 20 sec ⇒ Length of train = \[ 15 \times 20 = 300 \, \text{m} \] Time taken to pass platform = 36 sec ⇒ Total length = \[ 15 \times 36 = 540 \, \text{m} \] So, platform length = \[ 540 – 300 = \boxed{240 \, \text{m}} \] ✅ Final Answer: \(\boxed{240 \, \text{metres}}\) 🚄🚄 Two Trains Crossing Each Other Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other is: 9 9.6 10 10.8 Show Solution 📘 Step-by-Step Solution: Length of first train = 140 m Length of second train = 160 m Total distance to be covered = \[ 140 + 160 = 300 \, \text{m} \] Speed of first train = \[ 60 \, \text{km/hr} = 60 \times \frac{1000}{3600} = 16.67 \, \text{m/s} \] Speed of second train = \[ 40 \, \text{km/hr} = 40 \times \frac{1000}{3600} = 11.11 \, \text{m/s} \] Relative speed (opposite direction) = \[ 16.67 + 11.11 = 27.78 \, \text{m/s} \] Time to cross each other = \[ \frac{300}{27.78} \approx \boxed{10.8 \, \text{seconds}} \] ✅ Final Answer: \(\boxed{10.8 \, \text{seconds}}\) 🚆 Train Speed Problem Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? 120 metres 180 metres 324 metres 150 metres Show Solution 📘 Step-by-Step Solution: We use the formula: \[ \text{Distance} = \text{Speed} \times \text{Time} \] First, convert speed from km/hr to m/s: \[ 60 \, \text{km/hr} = 60 \times \frac{1000}{3600} = 16.67 \, \text{m/s} \] Now calculate distance using the time = 9 seconds: \[ \text{Distance} = 16.67 \times 9 = 150 \, \text{metres} \] ✅ Final Answer: \(\boxed{150 \, \text{metres}}\) 🚆 Train & Bridge Problem Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is: 200 m 225 m 245 m 250 m Show Solution 📘 Step-by-Step Solution: Total distance covered in crossing the bridge = Length of train + Length of bridge Speed = 45 km/hr = \[ 45 \times \frac{1000}{3600} = 12.5 \, \text{m/s} \] Time = 30 seconds Total Distance = Speed × Time \[ = 12.5 \times 30 = 375 \, \text{m} \] Train length = 130 m \[ \text{Bridge length} = 375 – 130 = \boxed{245 \, \text{m}} \] ✅ Final Answer: \(\boxed{245 \, \text{metres}}\) 🚄 Two Trains from Howrah and Patna Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. What is the ratio of their speeds? 2 : 3 4 : 3 6 : 7 9 : 16 Show Solution 📘 Step-by-Step Solution: Let the two trains meet at point M. 🧠 Key Concept: If two objects start at the same time and move towards each other, and after meeting, take t₁ and t₂ hours respectively to complete their journeys, then: \[ \text{Ratio of their speeds} = \sqrt{t_2} : \sqrt{t_1} \] Here, Time taken by train from Howrah after meeting = 9 hours Time taken by train from Patna after meeting = 16 hours So the ratio of speeds is: \[ \sqrt{16} : \sqrt{9} = 4 : 3 \] ✅ Final Answer: \(\boxed{4 : 3}\)

IIT JEE Maths Practice Paper 13– PYQs - Topic Calculus

IIT JEE Maths Practice Paper Part 13 Calculus (Previous Years’ Questions)

Test your preparation for IIT JEE Mathematics with these previous years’ Calculus questions. Includes differentiation, integration, limits, continuity, and application-based problems. Ideal for last-minute practice and concept revision. IIT JEE Maths Practice – Calculus 1. The derivative of \( e^{\tan x} \) is: \( \sec^2 x \cdot e^{\tan x} \) \( \tan x \cdot e^{\tan x} \) \( \sec x \cdot e^x \) \( \sec x \cdot \tan x \) 2. If \( f(x) = \ln(\sin x) \), then \( f'(x) \) equals: \( \cot x \) \( \frac{1}{\sin x} \) \( \frac{\cos x}{\sin x} \) \( \cos x \cdot \ln x \) 3. \( \int_0^1 x e^x \, dx \) is: \( e – 2 \) \( 1 \) \( 2e \) \( e – 1 \) 4. Limit \( \lim_{x \to 0} \frac{\sin x}{x} \) equals: 1 0 ∞ Does not exist 5. If \( f(x) = x^2 \), then \( \int f'(x) dx \) is: \( x^2 + C \) \( 2x + C \) \( 2x^2 + C \) \( x^3 + C \) 6. If \( \int_1^2 f(x)dx = 3 \), what is \( \int_1^2 5f(x)dx \)? 15 5 8 1.5 7. If \( y = x^x \), then \( \frac{dy}{dx} \) equals: \( x^x(1 + \ln x) \) \( x^x \ln x \) \( x \ln x \) \( \ln x + 1 \) 8. \( \int \frac{1}{x^2 + 1} dx \) is: \( \tan^{-1}(x) + C \) \( \ln(x^2 + 1) + C \) \( \frac{1}{x^2 + 1} + C \) \( \tan(x) + C \) 9. If a function is differentiable, it is always: Continuous Discontinuous Constant None 10. The area under the curve \( y = x^2 \) from 0 to 2 is: \( \frac{8}{3} \) \( 4 \) \( 2 \) \( \frac{4}{3} \) Submit